For $\small{f(x) =} \large{\frac{2}{x^2}}$, find $\small{f\;'(x)}$ using the definition $\small{f\;'(x) = \displaystyle\lim_{h\rightarrow 0}} \large{\frac{f(x + h) - f(x)}{h}}$.

$\small{f\;'(x) =}$

Using this, find the tangent line to the graph of $\small{y =} \large{\frac{2}{x^2}}$ at $\small{x = 1}$. Write the equation of the line in slope-intercept form.

$\small{y =}$

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