Evaluate the limits. $$f(x) = \begin{cases} 3 x^2 - 5 & x < -1 \\ 3 x^3 + 5 & -1 \leq x \leq 1 \\ 3 x^2 + 5 & x > 1 \end{cases}$$ Enter DNE if the limit does not exist.

a) $\displaystyle \lim_{x \to -1^-} f(x)$ =

b) $\displaystyle \lim_{x \to -1^+} f(x)$ =

c) $\displaystyle \lim_{x \to -1} f(x)$ =

d) $\displaystyle f(-1)$ =

e) $\displaystyle \lim_{x \to 1^-} f(x)$ =

f) $\displaystyle \lim_{x \to 1^+} f(x)$ =

g) $\displaystyle \lim_{x \to 1} f(x)$ =

h) $\displaystyle f(1)$ =