Fill in each blank to construct an $\epsilon$-$\delta$ proof showing that
$\displaystyle \lim_{x \to 2}\; 3 - x = 1.$
Where it asks for $\delta$ give the largest value that will work.

Proof. Let $> 0$ be given. Let $\delta$ be the product
$\delta =$( )($\epsilon$).
If
$|x -$$| <$
then after some algebra we arrive at
$|(3-x) -$$| <$
which is what we wanted to prove.

You can earn partial credit on this problem.