(a) Compute $(d/dx)(\sec^{-1}{x})$ at $x=-2$ if one defines $\sec^{-1}{x}$ as follows:

$\ \ \ y=\sec^{-1}{x}$ if $\sec{y}=x$ and $0\leq y < \pi/2$ or $\pi \leq y <3\pi/2$.

(b) Compute $(d/dx)(\sec^{-1}{x})$ at $x=-2$ if one defines $\sec^{-1}{x}$ as follows:

$\ \ \ y=\sec^{-1}{x}$ if $\sec{y}=x$ and $0\leq y \leq \pi$ and $y \neq 0$.

Express your answers only in terms of $x$.

(a) $y' =$

(b) $y' =$

You can earn partial credit on this problem.